Here is a Python solution using the concept of "Fast Power" in a recursive manner. This approach reduces the time complexity to O(log n).

```python
def myPow(x, n):
# base case
if n == 0:
return 1.0
# if n is negative, convert x to its reciprocal and n to positive
if n

Question

Here is a Python solution using the concept of "Fast Power" in a recursive manner. This approach reduces the time complexity to O(log n).

```python
def myPow(x, n):
    # base case
    if n == 0:
        return 1.0
    # if n is negative, convert x to its reciprocal and n to positive
    if n < 0:
        x = 1 / x
        n = -n
    # recursive case
    result = myPow(x, n // 2)
    if n % 2 == 0:
        return result * result
    else:
        return result * result * x
```

Here

Knowee AI · Accepted Answer

Here is a Python solution using the concept of "Fast Power" in a recursive manner. This approach reduces the time complexity to O(log n).

```python
def myPow(x, n):
    # base case
    if n == 0:
        return 1.0
    # if n is negative, convert x to its reciprocal and n to positive
    if n < 0:
        x = 1 / x
        n = -n
    # recursive case
    result = myPow(x, n // 2)
    if n % 2 == 0:
        return result * result
    else:
        return result * result * x
```

Here

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