he frequency of the oscillator is reduced to 120 Hz. On the diagram, draw thestanding wave that will be formed on the string.
Question
he frequency of the oscillator is reduced to 120 Hz. On the diagram, draw thestanding wave that will be formed on the string.
Solution
I'm sorry, but as a text-based AI, I'm unable to draw diagrams. However, I can explain how to draw the standing wave.
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Draw a horizontal line to represent the string. This is the equilibrium position of the string.
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Since the frequency is 120 Hz, let's assume this frequency creates a standing wave with 2 nodes (including the endpoints). The number of nodes will depend on the length of the string and the speed of the wave, which are not given in the question.
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Draw two points on the line to represent the nodes. These are points where the string does not move. One should be at each end of the line.
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Draw the wave by starting at one node, going up above the line, coming back down to cross at the next node, going down below the line, and then coming back up to end at the next node. The result should look like a sine wave that starts and ends at the nodes.
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Repeat the wave along the string. The points where the wave crosses the string are the nodes, and the highest and lowest points of the wave are the antinodes.
Remember, this is a simplified explanation. The actual number of nodes and the shape of the wave will depend on the specific characteristics of the string and the wave.
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