Find the number of addresses in the block containing the IP address 192.168.2.36/27.What are the first and the last addresses of this block?

To find the number of addresses in the block containing the IP address 192.168.2.36/27, we need to determine the subnet mask.

The /27 in the IP address notation represents the number of network bits in the subnet mask. In this case, it means that the first 27 bits of the IP address are the network bits, and the remaining 5 bits are the host bits.

To calculate the number of addresses in the block, we need to determine the number of possible combinations for the host bits. Since there are 5 host bits, there are 2^5 = 32 possible combinations.

However, we need to subtract 2 from this number because the first and last addresses in the block are reserved. The first address is the network address, and the last address is the broadcast address.

Therefore, the number of addresses in the block is 32 - 2 = 30.

To find the first and last addresses of this block, we need to determine the network address and the broadcast address.

The network address is obtained by setting all the host bits to 0. In this case, the network address is 192.168.2.32.

The broadcast address is obtained by setting all the host bits to 1. In this case, the broadcast address is 192.168.2.63.

So, the first address of the block is 192.168.2.32, and the last address is 192.168.2.63.