Find the output of the below program:int main(){ int str[]={'e','a','r','t','h'}; printf("A%c ",str); printf("A%s ",str); printf("A%c ",str[0]); return 0;}
Question
Find the output of the below program:int main(){ int str[]={'e','a','r','t','h'}; printf("A%c ",str); printf("A%s ",str); printf("A%c ",str[0]); return 0;}
Solution
The given program is written in C language. Let's analyze the code step by step to find the output.
- The program starts with the main function.
- Inside the main function, an integer array named "str" is declared and initialized with the ASCII values of the characters 'e', 'a', 'r', 't', and 'h'.
- The first printf statement is executed, which tries to print the character array "str" using the format specifier "%c". However, since "str" is an array, it decays into a pointer to the first element. So, it will print the ASCII value of the first character in the array, which is 'e'. Therefore, the output of this printf statement will be "Ae ".
- The second printf statement tries to print the character array "str" using the format specifier "%s". This format specifier is used to print strings. However, the array "str" is not null-terminated, so it will not be treated as a valid string. As a result, the behavior of this printf statement is undefined.
- The third printf statement tries to print the first element of the array "str" using the format specifier "%c". Since the first element is 'e', the output of this printf statement will be "Ae ".
- Finally, the main function returns 0, indicating successful execution of the program.
So, the expected output of the program will be: Ae A (undefined behavior) Ae
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