If a Δ has a height of 160 cm and an area of 1600 cm2, what would the length of the base be?

The formula for the area of a triangle is 1/2 * base * height.

Given that the area of the triangle is 1600 cm^2 and the height is 160 cm, we can substitute these values into the formula and solve for the base.

So, 1600 = 1/2 * base * 160.

To isolate the base, we first multiply both sides of the equation by 2 to get rid of the 1/2 on the right side:

3200 = base * 160.

Then, we divide both sides of the equation by 160 to solve for the base:

base = 3200 / 160 = 20 cm.

So, the length of the base of the triangle would be 20 cm.

The formula for the area of a triangle is 1/2 * base * height.

Given that the area (A) is 1600 cm^2 and the height (h) is 160 cm, you can substitute these values into the formula and solve for the base (b).

So, 1600 = 1/2 * b * 160.

To isolate b, you can first multiply both sides of the equation by 2 to get rid of the 1/2 on the right side:

3200 = b * 160.

Then, divide both sides by 160 to solve for b:

b = 3200 / 160 = 20 cm.

So, the length of the base of the triangle would be 20 cm.