The correct answer is "a lcm(a, b) b".

Here's why:

The least common multiple (lcm) of two integers a and b is the smallest positive integer that is divisible by both a and b.

Given that a b, the lcm(a, b) cannot be less than b because it must be divisible by b.

Also, the lcm(a, b) cannot be greater than a because a is already divisible by itself and is the larger number.

Therefore, the only possible option is that a lcm(a, b) b.

Question

The correct answer is "a > lcm(a, b) > b".

Here's why:

The least common multiple (lcm) of two integers a and b is the smallest positive integer that is divisible by both a and b.

Given that a > b, the lcm(a, b) cannot be less than b because it must be divisible by b.

Also, the lcm(a, b) cannot be greater than a because a is already divisible by itself and is the larger number.

Therefore, the only possible option is that a > lcm(a, b) > b.

Knowee AI · Accepted Answer

The correct answer is "a > lcm(a, b) > b".

Here's why:

The least common multiple (lcm) of two integers a and b is the smallest positive integer that is divisible by both a and b.

Given that a > b, the lcm(a, b) cannot be less than b because it must be divisible by b.

Also, the lcm(a, b) cannot be greater than a because a is already divisible by itself and is the larger number.

Therefore, the only possible option is that a > lcm(a, b) > b.

Q3 of 30 Marks 1 General Instructions 110% ×CloseTest time left: 55:19Select the correct answerIf a, b are integers such that a > b then lcm(a, b) lies in _________OptionsNone of thesea > b > lcm(a, b)a > lcm(a, b) > blcm(a, b) >= a > b