Put the quadratic into vertex form and state the coordinates of the vertex.y, equals, x, squared, plus, 8, x, plus, 15y=x 2 +8x+15

Sure, let's put the quadratic equation into vertex form. The vertex form of a quadratic function is y=a(x-h)²+k, where (h,k) is the vertex of the parabola.

The given quadratic function is y=x²+8x+15.

Step 1: Group the x terms together. y = (x² + 8x) + 15

Step 2: Complete the square. To do this, take the coefficient of x, divide by 2 and square the result. (8/2)² = 16. Add and subtract this inside the parenthesis. y = (x² + 8x + 16 - 16) + 15 y = ((x + 4)² - 16) + 15

Step 3: Simplify the equation. y = (x + 4)² - 1

So, the vertex form of the given quadratic function is y = (x + 4)² - 1.

The coordinates of the vertex (h,k) can be found by setting the terms inside the parenthesis to 0 and solving for x (which gives h), and substitifying h into the equation to find y (which gives k).

So, h = -4 and k = -1.

Therefore, the vertex of the parabola is (-4, -1).