Algebraic expressions (Part 1)INTRODUCTION TO ALGEBRAThe two terms shown here are like terms:2g3;โg32๐3;โ๐3Why are these like terms? Select the best explanation from the list below.Answer:
Question
Algebraic expressions (Part 1)INTRODUCTION TO ALGEBRAThe two terms shown here are like terms:2g3;โg32๐3;โ๐3Why are these like terms? Select the best explanation from the list below.Answer:
Solution
The terms 2g^3 and -g^3 are considered like terms because they have the same variable part, which is g^3. In algebra, like terms are terms that contain the same variables raised to the same power. The numerical coefficients do not have to be the same. In this case, the coefficients are 2 and -1, but since the variable part g^3 is the same, these are like terms.
Similar Questions
Algebraic expressions (Part 1)INTRODUCTION TO ALGEBRAHere are two terms:Term oneโ5a4Term twoโ4h2Term oneTerm twoโ5๐4โ4โ2Are these like terms or not?Answer:
๐(๐ฅ)=2๐ฅ2+4๐ฅโ5f(x)=2x 2 +4xโ5๐(๐ฅ)=6๐ฅ3โ2๐ฅ2+3g(x)=6x 3 โ2x 2 +3Find (๐โ๐)(๐ฅ)(fโg)(x).A.(๐โ๐)(๐ฅ)=6๐ฅ3โ4๐ฅ2โ4๐ฅ+8(fโg)(x)=6x 3 โ4x 2 โ4x+8B.(๐โ๐)(๐ฅ)=โ6๐ฅ3+4๐ฅ2+4๐ฅโ8(fโg)(x)=โ6x 3 +4x 2 +4xโ8C.(๐โ๐)(๐ฅ)=6๐ฅ3+4๐ฅโ2(fโg)(x)=6x 3 +4xโ2D.(๐โ๐)(๐ฅ)=โ6๐ฅ3+4๐ฅ2+4๐ฅโ2(fโg)(x)=โ6x 3 +4x 2 +4xโ2SUBMITarrow_backPREVIOUS
3ab, 6๐๐56๐๐5, 2ba are like terms True False
๐(๐ฅ)=2๐ฅ2+6๐ฅโ4f(x)=2x 2 +6xโ4๐(๐ฅ)=5๐ฅ3โ6๐ฅ2โ3g(x)=5x 3 โ6x 2 โ3Find (๐+๐)(๐ฅ)(f+g)(x).A.(๐+๐)(๐ฅ)=5๐ฅ3โ4๐ฅ2+6๐ฅโ7(f+g)(x)=5x 3 โ4x 2 +6xโ7B.(๐+๐)(๐ฅ)=5๐ฅ3+2๐ฅ2โ7(f+g)(x)=5x 3 +2x 2 โ7C.(๐+๐)(๐ฅ)=โ5๐ฅ3+8๐ฅ2+6๐ฅโ1(f+g)(x)=โ5x 3 +8x 2 +6xโ1D.(๐+๐)(๐ฅ)=7๐ฅ3โ7(f+g)(x)=7x 3 โ7SUBMITarrow_backPREVIOUS
Algebraic expressions (Part 2): ExponentsALGEBRAIC FRACTIONSSimplify each of the following expressions:INSTRUCTION: Use the ^ symbol to type an exponent if necessary. For example for g2๐2 type g^2.Answer:1. 6g4ร4g22g=6๐4ร4๐22๐= 2. 6g4+4g22g=6๐4+4๐22๐=2 attempts remaining
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