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Algebraic expressions (Part 1)INTRODUCTION TO ALGEBRAThe two terms shown here are like terms:2g3;โˆ’g32๐‘”3;โˆ’๐‘”3Why are these like terms? Select the best explanation from the list below.Answer:

Question

Algebraic expressions (Part 1)INTRODUCTION TO ALGEBRAThe two terms shown here are like terms:2g3;โˆ’g32๐‘”3;โˆ’๐‘”3Why are these like terms? Select the best explanation from the list below.Answer:

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Solution

The terms 2g^3 and -g^3 are considered like terms because they have the same variable part, which is g^3. In algebra, like terms are terms that contain the same variables raised to the same power. The numerical coefficients do not have to be the same. In this case, the coefficients are 2 and -1, but since the variable part g^3 is the same, these are like terms.

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Algebraic expressions (Part 1)INTRODUCTION TO ALGEBRAHere are two terms:Term oneโˆ’5a4Term twoโˆ’4h2Term oneTerm twoโˆ’5๐‘Ž4โˆ’4โ„Ž2Are these like terms or not?Answer:

๐‘“(๐‘ฅ)=2๐‘ฅ2+4๐‘ฅโˆ’5f(x)=2x 2 +4xโˆ’5๐‘”(๐‘ฅ)=6๐‘ฅ3โˆ’2๐‘ฅ2+3g(x)=6x 3 โˆ’2x 2 +3Find (๐‘“โˆ’๐‘”)(๐‘ฅ)(fโˆ’g)(x).A.(๐‘“โˆ’๐‘”)(๐‘ฅ)=6๐‘ฅ3โˆ’4๐‘ฅ2โˆ’4๐‘ฅ+8(fโˆ’g)(x)=6x 3 โˆ’4x 2 โˆ’4x+8B.(๐‘“โˆ’๐‘”)(๐‘ฅ)=โˆ’6๐‘ฅ3+4๐‘ฅ2+4๐‘ฅโˆ’8(fโˆ’g)(x)=โˆ’6x 3 +4x 2 +4xโˆ’8C.(๐‘“โˆ’๐‘”)(๐‘ฅ)=6๐‘ฅ3+4๐‘ฅโˆ’2(fโˆ’g)(x)=6x 3 +4xโˆ’2D.(๐‘“โˆ’๐‘”)(๐‘ฅ)=โˆ’6๐‘ฅ3+4๐‘ฅ2+4๐‘ฅโˆ’2(fโˆ’g)(x)=โˆ’6x 3 +4x 2 +4xโˆ’2SUBMITarrow_backPREVIOUS

3ab, 6๐‘Ž๐‘56๐‘Ž๐‘5, 2ba are like terms True False

๐‘“(๐‘ฅ)=2๐‘ฅ2+6๐‘ฅโˆ’4f(x)=2x 2 +6xโˆ’4๐‘”(๐‘ฅ)=5๐‘ฅ3โˆ’6๐‘ฅ2โˆ’3g(x)=5x 3 โˆ’6x 2 โˆ’3Find (๐‘“+๐‘”)(๐‘ฅ)(f+g)(x).A.(๐‘“+๐‘”)(๐‘ฅ)=5๐‘ฅ3โˆ’4๐‘ฅ2+6๐‘ฅโˆ’7(f+g)(x)=5x 3 โˆ’4x 2 +6xโˆ’7B.(๐‘“+๐‘”)(๐‘ฅ)=5๐‘ฅ3+2๐‘ฅ2โˆ’7(f+g)(x)=5x 3 +2x 2 โˆ’7C.(๐‘“+๐‘”)(๐‘ฅ)=โˆ’5๐‘ฅ3+8๐‘ฅ2+6๐‘ฅโˆ’1(f+g)(x)=โˆ’5x 3 +8x 2 +6xโˆ’1D.(๐‘“+๐‘”)(๐‘ฅ)=7๐‘ฅ3โˆ’7(f+g)(x)=7x 3 โˆ’7SUBMITarrow_backPREVIOUS

Algebraic expressions (Part 2): ExponentsALGEBRAIC FRACTIONSSimplify each of the following expressions:INSTRUCTION: Use the ^ symbol to type an exponent if necessary. For example for g2๐‘”2 type g^2.Answer:1. 6g4ร—4g22g=6๐‘”4ร—4๐‘”22๐‘”= 2. 6g4+4g22g=6๐‘”4+4๐‘”22๐‘”=2 attempts remaining

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