Type erasure is a concept in generics where the information on generics is used by the compiler but is not available at runtime. Considering this fact, what is the code equivalent to the following generated by the Java compiler for runtime use?ArrayList<String> list = new ArrayList<>();list.add("Oklahoma");String state = list.get(0);Group of answer choicesArrayList<Object> list = new ArrayList<>();list.add("Oklahoma");String state = list.get(0);ArrayList list = new ArrayList();list.add("Oklahoma");Object state = list.get(0);ArrayList list = new ArrayList();list.add("Oklahoma");String state = list.get(0);ArrayList list = new ArrayList();list.add("Oklahoma");String state = (String)(list.get(0));
Question
Type erasure is a concept in generics where the information on generics is used by the compiler but is not available at runtime. Considering this fact, what is the code equivalent to the following generated by the Java compiler for runtime use?ArrayList<String> list = new ArrayList<>();list.add("Oklahoma");String state = list.get(0);Group of answer choicesArrayList<Object> list = new ArrayList<>();list.add("Oklahoma");String state = list.get(0);ArrayList list = new ArrayList();list.add("Oklahoma");Object state = list.get(0);ArrayList list = new ArrayList();list.add("Oklahoma");String state = list.get(0);ArrayList list = new ArrayList();list.add("Oklahoma");String state = (String)(list.get(0));
Solution
The code equivalent to the given code, considering type erasure in Java generics, would be:
ArrayList list = new ArrayList();
list.add("Oklahoma");
Object state = list.get(0);
This is because, at runtime, the Java compiler erases all type parameters and replaces them with their bounds or with Object if the type parameters are unbounded. The resulting bytecode, thus, contains only ordinary classes, interfaces, and methods. Hence, the generic type information is not available at runtime.
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