What least number must be added to 1064 to get a number exactly divisible by 27?
Question
What least number must be added to 1064 to get a number exactly divisible by 27?
Solution
Step 1: Divide 1064 by 27.
1064 ÷ 27 = 39.40740740740741
Step 2: Round up the quotient to the nearest whole number.
The nearest whole number to 39.40740740740741 is 40.
Step 3: Multiply this whole number by 27.
40 x 27 = 1080
Step 4: Subtract the original number from this result.
1080 - 1064 = 16
So, the least number that must be added to 1064 to get a number exactly divisible by 27 is 16.
Similar Questions
What least number that should be added to 14887 so that it is completely divisible by 29?Select one:a. 17b. 19c. 21d. 5e. 7
What will be the Least Common Multiple of the numbers divisible by 3 between 26 and 32?
What will be the least number which when doubled becomes exactly divisible by 9, 15, 21, and 30?
Find the least number exactly divisible by 12, 15, 20 and 27.
What least number must be added to 1056, so that the sum is completely divisible by 23?231821
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.