What would be the size of the following union declaration? (Assuming size of double = 8, size of int = 4, size of char = 1)#include<studio.h>union uTemp { double a; int b[10]; char c; }u;a.4b.40c.8d.80
Question
What would be the size of the following union declaration? (Assuming size of double = 8, size of int = 4, size of char = 1)#include<studio.h>union uTemp { double a; int b[10]; char c; }u;a.4b.40c.8d.80
Solution 1
To determine the size of the union declaration, we need to calculate the total size of its members.
Given that the size of a double is 8, the size of an int is 4, and the size of a char is 1, we can calculate the size of the union as follows:
- The size of the double member 'a' is 8.
- The size of the int array member 'b' is 4 * 10 = 40.
- The size of the char member 'c' is 1.
To find the total size of the union, we take the maximum size among its members, which is 40 in this case. Therefore, the size of the union declaration would be 40.
Solution 2
To determine the size of the union declaration, we need to calculate the total size of its members.
Given that the size of a double is 8, the size of an int is 4, and the size of a char is 1, we can calculate the size of the union as follows:
- The size of the double member 'a' is 8.
- The size of the int array member 'b' is 4 * 10 = 40.
- The size of the char member 'c' is 1.
To find the total size of the union, we take the maximum size among its members, which is 40 in this case. Therefore, the size of the union declaration would be 40.
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