x = [[0], [1]]print(len(' '.join(list(map(str, x)))))
Question
x = [[0], [1]]print(len(' '.join(list(map(str, x)))))
Solution
The code you provided is written in Python. Here's a step-by-step explanation of what it does:
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x = [[0], [1]]: This line creates a list of lists, where each sub-list contains a single integer. -
map(str, x): This line converts each sub-list inxto a string. Themap()function applies thestr()function to each element inx. The result is an iterable where each element is a string representation of the sub-lists inx, i.e.,['[0]', '[1]']. -
' '.join(list(map(str, x))): This line joins the elements of the iterable created in the previous step into a single string, with a space (' ') as the separator. Thelist()function is used to convert the iterable to a list before joining. The result is the string'[0] [1]'. -
len(' '.join(list(map(str, x)))): This line calculates the length of the string created in the previous step. The length of a string is the number of characters it contains. In this case, the length is 7, because the string'[0] [1]'contains 7 characters, including the space and the brackets. -
print(len(' '.join(list(map(str, x))))): This line prints the result calculated in the previous step. So, the output of the entire code is7.
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