You're writing a Bash script to process a list of filenames stored in a file, and for each file, you need to extract the base filename (without the path or extension). Which command correctly extracts the base filename for each line in the file?0.5 Marksfor filename in $(cat filenames.txt); doecho "$(basename $filename)"donecat filenames.txt | xargs -I{} basename {} | echofind . -type f -exec basename {} \; | cat > filenames.txtfor line in $(cat filenames.txt); dofilename=$(basename $line)echo "$filename"donewhile read line; dofilename=$(basename "$line")echo "$filename"done < filenames.txt

Question

You're writing a Bash script to process a list of filenames stored in a file, and for each file, you need to extract the base filename (without the path or extension). Which command correctly extracts the base filename for each line in the file?0.5 Marksfor filename in $(cat filenames.txt); doecho "$ (basename $filename)"donecat filenames.txt | xargs -I{} basename {} | echofind . -type f -exec basename {} \; | cat > filenames.txtfor line in$ (cat filenames.txt); dofilename= $(basename$ line)echo " $filename"donewhile read line; dofilename=$ (basename " $line")echo "$ filename"done < filenames.txt

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Solution

The correct command to extract the base filename for each line in the file is:

while read line; do
filename=$(basename "$line")
echo "$filename"
done < filenames.txt

This command reads each line from the file filenames.txt, uses the basename command to extract the base filename from each line, and then echoes (prints) the base filename. The while read line; do...done < filenames.txt structure is a common idiom in Bash for processing a file line by line.

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