Find the general indefinite integral. (Use C for the constant of integration.)u6 − 4u5 − u3 + 29 du

To find the indefinite integral of the function u^6 - 4u^5 - u^3 + 29 with respect to u, we apply the power rule for integration, which states that the integral of u^n du is (1/(n+1))u^(n+1).

Step 1: Integrate u^6 du The integral of u^6 du is (1/(6+1))u^(6+1) = (1/7)u^7.

Step 2: Integrate -4u^5 du The integral of -4u^5 du is -4*(1/(5+1))u^(5+1) = -(2/3)u^6.

Step 3: Integrate -u^3 du The integral of -u^3 du is -(1/(3+1))u^(3+1) = -(1/4)u^4.

Step 4: Integrate 29 du The integral of 29 du is 29u.

Step 5: Add the constant of integration C The general indefinite integral of the function is (1/7)u^7 - (2/3)u^6 - (1/4)u^4 + 29u + C.