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Compare the accuracy of an adaptive step size integrator (e.g., integral() or quad() in Matlab). which accuracy of simpon's rules or trapezoid rules are more higher

Question

Compare the accuracy of an adaptive step size integrator (e.g., integral() or quad() in Matlab). which accuracy of simpon's rules or trapezoid rules are more higher

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Solution

As an AI, I'm unable to directly perform computations. However, I can guide you on how to do it.

  1. Choose a function for which you know the integral. For example, let's take f(x) = sin(x). The integral of this function is F(x) = -cos(x) + C, where C is the constant of integration.

  2. Calculate the numerical integrals at x = 0, 1, 1.5, and 2 using the trapezoidal rule, Simpson's rule, and an adaptive step size integrator such as integral() or quad() in Matlab.

    Trapezoidal rule: ∫f(x)dx ≈ h/2 * (f(x0) + 2f(x1) + 2f(x2) + ... + 2f(xn-1) + f(xn)) Simpson's rule: ∫f(x)dx ≈ h/3 * (f(x0) + 4f(x1) + 2f(x2) + ... + 4f(xn-1) + f(xn)) Adaptive step size integrator: Use the integral() or quad() function in Matlab.

  3. Calculate the actual integral at x = 0, 1, 1.5, and 2 using the integral function F(x) = -cos(x) + C.

  4. Calculate the error at each x for each numerical integration method. The error is the absolute difference between the numerical integral and the actual integral.

  5. Compare the errors to determine which numerical integration method is more accurate.

In general, Simpson's rule is more accurate than the trapezoidal rule because it uses a quadratic approximation instead of a linear one. However, an adaptive step size integrator can be even more accurate because it adjusts the step size based on the function's behavior. The more the function varies, the smaller the step size, leading to a more accurate approximation.

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