This problem can be solved using the concept of man-days (a unit of work that represents the amount of work done by an individual in a day).

Step 1: Let's assume the amount of work done by 1 man in 1 day is m and the amount of work done by 1 boy in 1 day is b.

Step 2: According to the first condition, 6 men and 8 boys can do the work in 10 days. So, we can write this as: 10(6m + 8b) = W, where W is the total work.

Step 3: According to the second condition, 26 men and 48 boys can do the same work in 2 days. So, we can write this as: 2(26m + 48b) = W.

Step 4: Now, we have two equations with two variables (m and b). We can solve these equations to find the values of m and b.

Step 5: Once we have the values of m and b, we can find the time taken by 15 men and 20 boys to do the same work. This can be found by dividing the total work W by the work done by 15 men and 20 boys in a day, i.e., (15m + 20b).

The answer will be one of the options: 4 days, 5 days, 6 days, or 7 days.

Question

This problem can be solved using the concept of man-days (a unit of work that represents the amount of work done by an individual in a day).

Step 1: Let's assume the amount of work done by 1 man in 1 day is m and the amount of work done by 1 boy in 1 day is b.

Step 2: According to the first condition, 6 men and 8 boys can do the work in 10 days. So, we can write this as: 10(6m + 8b) = W, where W is the total work.

Step 3: According to the second condition, 26 men and 48 boys can do the same work in 2 days. So, we can write this as: 2(26m + 48b) = W.

Step 4: Now, we have two equations with two variables (m and b). We can solve these equations to find the values of m and b.

Step 5: Once we have the values of m and b, we can find the time taken by 15 men and 20 boys to do the same work. This can be found by dividing the total work W by the work done by 15 men and 20 boys in a day, i.e., (15m + 20b).

The answer will be one of the options: 4 days, 5 days, 6 days, or 7 days.

Knowee AI · Accepted Answer

This problem can be solved using the concept of man-days (a unit of work that represents the amount of work done by an individual in a day).

Step 1: Let's assume the amount of work done by 1 man in 1 day is m and the amount of work done by 1 boy in 1 day is b.

Step 2: According to the first condition, 6 men and 8 boys can do the work in 10 days. So, we can write this as: 10(6m + 8b) = W, where W is the total work.

Step 3: According to the second condition, 26 men and 48 boys can do the same work in 2 days. So, we can write this as: 2(26m + 48b) = W.

Step 4: Now, we have two equations with two variables (m and b). We can solve these equations to find the values of m and b.

Step 5: Once we have the values of m and b, we can find the time taken by 15 men and 20 boys to do the same work. This can be found by dividing the total work W by the work done by 15 men and 20 boys in a day, i.e., (15m + 20b).

The answer will be one of the options: 4 days, 5 days, 6 days, or 7 days.

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:4 days5 days6 days7 days

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