Consider the equations of motion in the vertical and horizontal directions Vertical Motion Horizontal Motionu 12.68 ms−1 27.15 ms−1v 0 ms−1 27.15 ms−1a +9.81 ms−2 0 ms−2t s 50 m D m ?Step 4: Calculate the time of flight from the vertical motion
Question
Consider the equations of motion in the vertical and horizontal directions Vertical Motion Horizontal Motionu 12.68 ms−1 27.15 ms−1v 0 ms−1 27.15 ms−1a +9.81 ms−2 0 ms−2t s 50 m D m ?Step 4: Calculate the time of flight from the vertical motion
Solution
To calculate the time of flight from the vertical motion, we can use the equation of motion:
v = u + at
where: v = final velocity = 0 ms^-1 (since the object is at rest at its highest point) u = initial velocity = 12.68 ms^-1 a = acceleration = +9.81 ms^-2 (acceleration due to gravity)
Rearranging the equation to solve for time (t), we get:
t = (v - u) / a
Substituting the given values, we get:
t = (0 - 12.68) / 9.81 = -12.68 / 9.81 = -1.29 s
However, time cannot be negative. The negative sign indicates that the direction of initial velocity is opposite to the direction of acceleration, which is expected as the object is thrown upwards against gravity. Therefore, the time of flight is 1.29 seconds.
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