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The hybridization and magnetic behaviour of cobalt ion in [Co(NH3)6]3+ complex, respectively issp3d2 and diamagneticd2sp3 and paramagneticd2sp3 and diamagneticsp3d2 and paramagnetic

Question

The hybridization and magnetic behaviour of cobalt ion in [Co(NH3)6]3+ complex, respectively issp3d2 and diamagneticd2sp3 and paramagneticd2sp3 and diamagneticsp3d2 and paramagnetic

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Solution

The hybridization and magnetic behaviour of cobalt ion in [Co(NH3)6]3+ complex is d2sp3 and diamagnetic.

Here's the step by step explanation:

  1. The oxidation state of cobalt in the given complex is +3. The electronic configuration of Co in ground state is [Ar] 3d7 4s2. In the +3 oxidation state, it will be [Ar] 3d6.

  2. In the complex [Co(NH3)6]3+, the central metal ion Co3+ is surrounded by 6 NH3 ligands. These ligands are strong field ligands and cause pairing of unpaired 3d electrons.

  3. After pairing, the 3d, 4s and 4p orbitals are hybridized to give d2sp3 hybridization.

  4. As all the electrons are paired, the complex is diamagnetic in nature.

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Similar Questions

Among [Ni(CO)4], [NiCl4]2–, [Co(NH3)4Cl2]Cl, Na3[CoF6], Na2O2 and CsO2, the total number of paramagnetic species is

How many ions are produced from the complex [Co(NH3)6]Cl2

The cobalt(III) pentammine complex, [Co(NH3)5Cl]2+, consists of a central cobalt cation with coordinate covalent bonds to five neutral ammonia molecules and a chloride anion, which act as ligands.  In an aqueous solution with a pH > 10, the complex readily undergoes a ligand exchange via base hydrolysis as shown in Reaction 1.[Co(NH3)5Cl]2++OH−⟶[Co(NH3)5(OH)]2++Cl−CoNH35Cl2++OH-⟶CoNH35OH2++Cl-Reaction 1Researchers have proposed that Reaction 1 might proceed by either a bimolecular nucleophilic substitution (an SN2 mechanism) as shown in Figure 1, or by a unimolecular nucleophilic substitution of the complex's conjugate base (an SN1CB mechanism) as shown in Figure 2.Figure 1  SN2 mechanism proposed for Reaction 1Figure 2  SN1CB mechanism proposed for Reaction 1In the proposed SN2 mechanism, the OH− ion functions as a nucleophile that attacks the central Co atom in the complex.  Accordingly, the nucleophilic attack results in a transition state in which the existing Co–Cl bond breaks and a new Co–OH bond forms in a single step.In contrast, the SN1CB mechanism proposes that the reaction occurs in multiple steps in which OH− initially acts as a base to deprotonate one of the coordinately bonded ammine ligands to form a hexa-coordinated intermediate with an amido (NH2−) ligand (Step 1).  The Cl− ligand in the amido intermediate then dissociates to form a pentacoordinated intermediate (Step 2).  A water molecule from the solution then coordinates with the Co atom of the pentacoordinated intermediate to form an aquo complex (Step 3).  A solvent-mediated proton transfer from the aquo to the amido ligand yields the final base-hydrolysis product (Step 4). Question 38To evaluate the proposed mechanisms, researchers attempted to modify Reaction 1 by replacing the [Co(NH3)5Cl]2+ complex with the complex shown above, which contains C5H5N (pyridine) ligands instead of NH3 ligands, but no reaction occurred.  Assuming that steric hindrance is not a factor in the reaction, this result provides evidence in support of the:A.SN2 mechanism, because the experimental change resulted in no reaction.B.SN2 mechanism, because the pyridine ligands have a negative formal charge that repels the OH− ion.C.SN1CB mechanism, because the leaving group is the same in both the original and the modified reaction.D.SN1CB mechanism, because an N–H bond is required to form the proposed intermediate.

[Co(NH3)6]3+ and [CoF6]3− are respectively known as:

Which of the following statement is not correct?[Ni(CN)4]−2 and [Ni(CO)4] have the same magnetic moment[NiCl4]−2 and [PtCl4]−2 have different shape.Hybrid state of Co in [Co(Ox)3]−3 is sp3 d2In brown-ring complex [Fe(H2O)5NO]SO4 oxidation state of Fe is +1

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