The hybridization and magnetic behaviour of cobalt ion in [Co(NH3)6]3+ complex, respectively issp3d2 and diamagneticd2sp3 and paramagneticd2sp3 and diamagneticsp3d2 and paramagnetic
Question
The hybridization and magnetic behaviour of cobalt ion in [Co(NH3)6]3+ complex, respectively issp3d2 and diamagneticd2sp3 and paramagneticd2sp3 and diamagneticsp3d2 and paramagnetic
Solution
The hybridization and magnetic behaviour of cobalt ion in [Co(NH3)6]3+ complex is d2sp3 and diamagnetic.
Here's the step by step explanation:
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The oxidation state of cobalt in the given complex is +3. The electronic configuration of Co in ground state is [Ar] 3d7 4s2. In the +3 oxidation state, it will be [Ar] 3d6.
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In the complex [Co(NH3)6]3+, the central metal ion Co3+ is surrounded by 6 NH3 ligands. These ligands are strong field ligands and cause pairing of unpaired 3d electrons.
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After pairing, the 3d, 4s and 4p orbitals are hybridized to give d2sp3 hybridization.
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As all the electrons are paired, the complex is diamagnetic in nature.
Similar Questions
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How many ions are produced from the complex [Co(NH3)6]Cl2
The cobalt(III) pentammine complex, [Co(NH3)5Cl]2+, consists of a central cobalt cation with coordinate covalent bonds to five neutral ammonia molecules and a chloride anion, which act as ligands. In an aqueous solution with a pH > 10, the complex readily undergoes a ligand exchange via base hydrolysis as shown in Reaction 1.[Co(NH3)5Cl]2++OH−⟶[Co(NH3)5(OH)]2++Cl−CoNH35Cl2++OH-⟶CoNH35OH2++Cl-Reaction 1Researchers have proposed that Reaction 1 might proceed by either a bimolecular nucleophilic substitution (an SN2 mechanism) as shown in Figure 1, or by a unimolecular nucleophilic substitution of the complex's conjugate base (an SN1CB mechanism) as shown in Figure 2.Figure 1 SN2 mechanism proposed for Reaction 1Figure 2 SN1CB mechanism proposed for Reaction 1In the proposed SN2 mechanism, the OH− ion functions as a nucleophile that attacks the central Co atom in the complex. Accordingly, the nucleophilic attack results in a transition state in which the existing Co–Cl bond breaks and a new Co–OH bond forms in a single step.In contrast, the SN1CB mechanism proposes that the reaction occurs in multiple steps in which OH− initially acts as a base to deprotonate one of the coordinately bonded ammine ligands to form a hexa-coordinated intermediate with an amido (NH2−) ligand (Step 1). The Cl− ligand in the amido intermediate then dissociates to form a pentacoordinated intermediate (Step 2). A water molecule from the solution then coordinates with the Co atom of the pentacoordinated intermediate to form an aquo complex (Step 3). A solvent-mediated proton transfer from the aquo to the amido ligand yields the final base-hydrolysis product (Step 4). Question 38To evaluate the proposed mechanisms, researchers attempted to modify Reaction 1 by replacing the [Co(NH3)5Cl]2+ complex with the complex shown above, which contains C5H5N (pyridine) ligands instead of NH3 ligands, but no reaction occurred. Assuming that steric hindrance is not a factor in the reaction, this result provides evidence in support of the:A.SN2 mechanism, because the experimental change resulted in no reaction.B.SN2 mechanism, because the pyridine ligands have a negative formal charge that repels the OH− ion.C.SN1CB mechanism, because the leaving group is the same in both the original and the modified reaction.D.SN1CB mechanism, because an N–H bond is required to form the proposed intermediate.
[Co(NH3)6]3+ and [CoF6]3− are respectively known as:
Which of the following statement is not correct?[Ni(CN)4]−2 and [Ni(CO)4] have the same magnetic moment[NiCl4]−2 and [PtCl4]−2 have different shape.Hybrid state of Co in [Co(Ox)3]−3 is sp3 d2In brown-ring complex [Fe(H2O)5NO]SO4 oxidation state of Fe is +1
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