Butan-1-ol (Mr = 74) can be converted into 1-bromobutane (Mr = 137) by the reaction with sodium bromide (Mr = 103) and sulfuric acid (Mr = 98), according to the following equation:C4H9OH(l) + NaBr(aq) + H2SO4(aq) → C4H9Br(l) + NaHSO4(aq) + H2O(l)Given that 1-bromobutane is the desired product, what is the % atom economy for this reaction, to 3 significant figures?Answer:

To calculate the atom economy for the reaction, we need to follow these steps:

1. Calculate the molar mass of the desired product, 1-bromobutane. The molar mass (Mr) is given as 137.

2. Calculate the total molar mass of all reactants. This is the sum of the molar masses of butan-1-ol, sodium bromide, and sulfuric acid, which is 74 + 103 + 98 = 275.

3. The atom economy is the ratio of the molar mass of the desired product to the total molar mass of all reactants, expressed as a percentage. So, Atom Economy = (Mr of desired product / Total Mr of reactants) x 100%.

4. Substituting the values we have, Atom Economy = (137 / 275) x 100% = 49.81818182%.

5. To 3 significant figures, the atom economy is 49.8%.