The reaction of CH3COOH (a weak acid) with NaOH (a strong base) forms CH3COONa (a salt) and water, as shown below.CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l)If a sample of CH3COONa(s) salt is isolated and dissolved in pure water, the estimated pH of the resulting salt solution is:A.< 4.B.> 4 and < 7.C.= 7.D.> 7.
Question
The reaction of CH3COOH (a weak acid) with NaOH (a strong base) forms CH3COONa (a salt) and water, as shown below.CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l)If a sample of CH3COONa(s) salt is isolated and dissolved in pure water, the estimated pH of the resulting salt solution is:A.< 4.B.> 4 and < 7.C.= 7.D.> 7.
Solution
The salt CH3COONa is formed from a weak acid (CH3COOH) and a strong base (NaOH). When this salt is dissolved in water, it will undergo hydrolysis. The anion (CH3COO-) from the salt will react with water to form OH- ions, which increases the pH of the solution. Therefore, the pH of the resulting solution will be greater than 7. So, the correct answer is D. > 7.
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