What does this code print?* print_something - function to print something** Return: Always 0**/int print_something(int num){ int i, j; for (i = 0; i < num + 1; i++) { for (j = 0; j < num + 1; j++) { printf("%d", i * j); if (j < num) { printf(", "); } } printf("\n"); } return (0);}The numbers 0 to n, n timesThe n times table, excluding zeroThe n times table, starting with 0I don't know
Question
What does this code print?* print_something - function to print something** Return: Always 0**/int print_something(int num){ int i, j; for (i = 0; i < num + 1; i++) { for (j = 0; j < num + 1; j++) { printf("%d", i * j); if (j < num) { printf(", "); } } printf("\n"); } return (0);}The numbers 0 to n, n timesThe n times table, excluding zeroThe n times table, starting with 0I don't know
Solution
The code prints the n times table, starting with 0.
Here's a step-by-step explanation:
-
The function
print_something(int num)is defined, which takes an integernumas an argument. -
Two integer variables
iandjare declared. -
A for loop is initiated with
iranging from 0 tonum(inclusive). -
Inside this loop, another for loop is initiated with
jranging from 0 tonum(inclusive). -
Inside the inner loop, the product of
iandjis printed. Ifjis less thannum, a comma and a space are printed. -
After the inner loop finishes, a newline character is printed.
-
This process repeats until the outer loop finishes.
-
The function then returns 0.
So, for a given num, this function prints a multiplication table from 0 to num, with each row and column representing the numbers from 0 to num.
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