Solve and give interval notation for the solution set. Then graph the solution set.-6x + 1 ≥ 13 or 3x + 3 ≥ -9

Sure, let's solve these inequalities step by step.

First, let's solve -6x + 1 ≥ 13:

• Subtract 1 from both sides to get -6x ≥ 12.
• Divide both sides by -6 to get x ≤ -2. Remember, when you divide or multiply by a negative number, you must flip the inequality sign.

Second, let's solve 3x + 3 ≥ -9:

• Subtract 3 from both sides to get 3x ≥ -12.
• Divide both sides by 3 to get x ≥ -4.

So, the solution to the inequalities is x ≤ -2 or x ≥ -4.

In interval notation, this is written as (-∞, -2] U [-4, ∞).

To graph this, you would draw a number line, put a closed circle at -2 and -4, draw a line to the left of -2 and to the right of -4, and leave the area between -2 and -4 blank.