A bowl contains 5 red balls, 3 green balls, and 2 white balls. if one ball is chosen at randoma. What is the probability that a red ball will be chosen?b. What is probability that a green ball will not be chosen?c. What is the probability that a white ball will be chosen?
Question
A bowl contains 5 red balls, 3 green balls, and 2 white balls. if one ball is chosen at randoma. What is the probability that a red ball will be chosen?b. What is probability that a green ball will not be chosen?c. What is the probability that a white ball will be chosen?
Solution
a. The total number of balls is 5 (red) + 3 (green) + 2 (white) = 10 balls. The probability of choosing a red ball is the number of red balls divided by the total number of balls. So, the probability is 5/10 = 0.5 or 50%.
b. The probability that a green ball will not be chosen is 1 minus the probability that a green ball will be chosen. The probability of choosing a green ball is 3/10 = 0.3 or 30%. So, the probability that a green ball will not be chosen is 1 - 0.3 = 0.7 or 70%.
c. The probability of choosing a white ball is the number of white balls divided by the total number of balls. So, the probability is 2/10 = 0.2 or 20%.
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