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There are n pieces arranged in a line, and each piece is colored either by 'A' or by 'B'. You are given a string colors of length n where colors[i] is the color of the ith piece.Alice and Bob are playing a game where they take alternating turns removing pieces from the line. In this game, Alice moves first.Alice is only allowed to remove a piece colored 'A' if both its neighbors are also colored 'A'. She is not allowed to remove pieces that are colored 'B'.Bob is only allowed to remove a piece colored 'B' if both its neighbors are also colored 'B'. He is not allowed to remove pieces that are colored 'A'.Alice and Bob cannot remove pieces from the edge of the line.If a player cannot make a move on their turn, that player loses and the other player wins.Assuming Alice and Bob play optimally, return true if Alice wins, or return false if Bob wins. Example 1:Input: colors = "AAABABB"Output: trueExplanation:AAABABB -> AABABBAlice moves first.She removes the second 'A' from the left since that is the only 'A' whose neighbors are both 'A'.Now it's Bob's turn.Bob cannot make a move on his turn since there are no 'B's whose neighbors are both 'B'.Thus, Alice wins, so return true.Example 2:Input: colors = "AA"Output: falseExplanation:Alice has her turn first.There are only two 'A's and both are on the edge of the line, so she cannot move on her turn.Thus, Bob wins, so return false.Example 3:Input: colors = "ABBBBBBBAAA"Output: falseExplanation:ABBBBBBBAAA -> ABBBBBBBAAAlice moves first.Her only option is to remove the second to last 'A' from the right.ABBBBBBBAA -> ABBBBBBAANext is Bob's turn.He has many options for which 'B' piece to remove. He can pick any.On Alice's second turn, she has no more pieces that she can remove.Thus, Bob wins, so return false.

Question

There are n pieces arranged in a line, and each piece is colored either by 'A' or by 'B'. You are given a string colors of length n where colors[i] is the color of the ith piece.Alice and Bob are playing a game where they take alternating turns removing pieces from the line. In this game, Alice moves first.Alice is only allowed to remove a piece colored 'A' if both its neighbors are also colored 'A'. She is not allowed to remove pieces that are colored 'B'.Bob is only allowed to remove a piece colored 'B' if both its neighbors are also colored 'B'. He is not allowed to remove pieces that are colored 'A'.Alice and Bob cannot remove pieces from the edge of the line.If a player cannot make a move on their turn, that player loses and the other player wins.Assuming Alice and Bob play optimally, return true if Alice wins, or return false if Bob wins. Example 1:Input: colors = "AAABABB"Output: trueExplanation:AAABABB -> AABABBAlice moves first.She removes the second 'A' from the left since that is the only 'A' whose neighbors are both 'A'.Now it's Bob's turn.Bob cannot make a move on his turn since there are no 'B's whose neighbors are both 'B'.Thus, Alice wins, so return true.Example 2:Input: colors = "AA"Output: falseExplanation:Alice has her turn first.There are only two 'A's and both are on the edge of the line, so she cannot move on her turn.Thus, Bob wins, so return false.Example 3:Input: colors = "ABBBBBBBAAA"Output: falseExplanation:ABBBBBBBAAA -> ABBBBBBBAAAlice moves first.Her only option is to remove the second to last 'A' from the right.ABBBBBBBAA -> ABBBBBBAANext is Bob's turn.He has many options for which 'B' piece to remove. He can pick any.On Alice's second turn, she has no more pieces that she can remove.Thus, Bob wins, so return false.

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Solution

This problem can be solved by using a simple approach. The idea is to count the number of 'A's and 'B's that are surrounded by the same color on both sides. If the count of such 'A's is more than the count of such 'B's, Alice will win, otherwise Bob will win. Here is a step by step solution:

  1. Initialize two counters, countA and countB, to zero. These will keep track of the number of 'A's and 'B's that are surrounded by the same color on both sides.

  2. Iterate over the string from the second character to the second last character. For each character, check if it is surrounded by the same color on both sides. If it is an 'A' and is surrounded by 'A's, increment countA. If it is a 'B' and is surrounded by 'B's, increment countB.

  3. After the iteration, compare countA and countB. If countA is more than countB, return true indicating that Alice will win. If countB is more than countA, return false indicating that Bob will win.

  4. If countA and countB are equal, it means that neither Alice nor Bob can make a move. In this case, return false as Alice moves first and she will not be able to make a move.

This solution works because Alice and Bob will always remove a piece if they can, as not doing so would give the other player an advantage. Also, they will always choose to remove a piece that is surrounded by the same color on both sides, as this will reduce the number of possible moves for the other player in their next turn.

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Similar Questions

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A string game is played by the children in a primary school.Given a string S , the children must check if it is a palindrome.A palindrome is a word, phrase, or sequence that reads the same backward as forward.If  S is a palindrome , then the children must say the number of characters in that string.If S is not a palindrome , then the children must say the reverse of the string.Write a function game and implement the above scenario.

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