Car rental agency A charges ₹50 per day plus ₹10 per kilometer driven. Agency B charges ₹20 per day plus ₹30 per kilometer driven. For a one-day rental it is cheaper to rent from agency A if you drive more than how much than agency B?1 pointA. 50 KilometerB. 100 KilometerC. 125 KilometerD. 150 Kilometer
Question
Car rental agency A charges ₹50 per day plus ₹10 per kilometer driven. Agency B charges ₹20 per day plus ₹30 per kilometer driven. For a one-day rental it is cheaper to rent from agency A if you drive more than how much than agency B?1 pointA. 50 KilometerB. 100 KilometerC. 125 KilometerD. 150 Kilometer
Solution
To solve this problem, we need to find the point at which the cost of renting from Agency A is equal to the cost of renting from Agency B.
Let's denote the number of kilometers driven as x.
The cost for Agency A is ₹50 (daily charge) + ₹10x (charge per kilometer). So, the total cost for Agency A is: 50 + 10x.
The cost for Agency B is ₹20 (daily charge) + ₹30x (charge per kilometer). So, the total cost for Agency B is: 20 + 30x.
We set these two equations equal to each other to find the break-even point:
50 + 10x = 20 + 30x
Solving for x gives:
20x = 30
x = 30/20 = 1.5 kilometers
So, if you drive more than 1.5 kilometers, it would be cheaper to rent from Agency A.
However, this is not one of the options given. It seems there may be a mistake in the problem or the answer choices.
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