An object of size 5 cm is kept at a distance of 25 cm from the Optical centre of a converging lens of focal length 10 cm. Calculate the  size of the image. (along with sign).

To calculate the size of the image formed by a converging lens, we can use the lens formula:

1/f = 1/v - 1/u

Where: f = focal length of the lens v = image distance from the lens u = object distance from the lens

Given: f = 10 cm u = -25 cm (negative sign indicates that the object is placed on the same side as the incident light) Size of the object = 5 cm

First, let's calculate the image distance (v) using the lens formula:

1/10 = 1/v - 1/-25

Simplifying the equation:

1/10 = 1/v + 1/25

Multiplying both sides by 250v:

25v = 250 + 10v

Subtracting 10v from both sides:

15v = 250

Dividing both sides by 15:

v = 250/15

v ≈ 16.67 cm

Now, we can calculate the size of the image using the magnification formula:

magnification (m) = -v/u

Substituting the values:

m = -16.67 / -25

Simplifying:

m ≈ 0.67

The negative sign indicates that the image is inverted.

Finally, we can calculate the size of the image using the magnification formula:

Size of the image = magnification * size of the object

Size of the image = 0.67 * 5 cm

Size of the image ≈ 3.33 cm

Therefore, the size of the image formed by the converging lens is approximately 3.33 cm, with a negative sign indicating that it is inverted.