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What is the result of the following statements?1: public class Test {2:      public void print(byte x) {3:           System.out.print("byte");4:         }5:      public void print(int x) {6:        System.out.print("int");7:         }8:      public void print(float x) {9:         System.out.print("float");10:       }11:     public void print(Object x) {12:       System.out.print("Object");13:       }14:     public static void main(String[] args) {15:        Test t = new Test();16:         short s = 123;17:         t.print(s);18:         t.print(true);19:         t.print(6.789);20:      }21: }*A. bytefloatObjectB. intfloatObjectC. byteObjectfloatD. intObjectfloatE. intObjectObjectF. byteObjectObject

Question

What is the result of the following statements?1: public class Test {2:      public void print(byte x) {3:           System.out.print("byte");4:         }5:      public void print(int x) {6:        System.out.print("int");7:         }8:      public void print(float x) {9:         System.out.print("float");10:       }11:     public void print(Object x) {12:       System.out.print("Object");13:       }14:     public static void main(String[] args) {15:        Test t = new Test();16:         short s = 123;17:         t.print(s);18:         t.print(true);19:         t.print(6.789);20:      }21: }*A. bytefloatObjectB. intfloatObjectC. byteObjectfloatD. intObjectfloatE. intObjectObjectF. byteObjectObject

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Solution

The result of the given Java code would be "intObjectfloat".

Here's the step by step explanation:

  1. The Test class is created with four overloaded print methods, each accepting different types of parameters: byte, int, float, and Object.

  2. In the main method, a Test object t is created.

  3. A short variable s is declared with the value 123. When t.print(s) is called, the print(int x) method is invoked because in Java, a short can be automatically promoted to int if no method exists that explicitly takes a short parameter. So, "int" is printed.

  4. Next, t.print(true) is called. Since there's no print method that accepts a boolean parameter, the print(Object x) method is invoked because in Java, a boolean can be boxed into a Boolean object. So, "Object" is printed.

  5. Finally, t.print(6.789) is called. This is a double literal, but since there's no print method that accepts a double parameter, it's automatically downcasted to float (losing some precision in the process) and the print(float x) method is invoked. So, "float" is printed.

So, the final output is "intObjectfloat", which corresponds to option D.

This problem has been solved

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