Evaluate cot(tan−1(2𝑥) + cot−1(2𝑥)).
Question
Evaluate cot(tan−1(2𝑥) + cot−1(2𝑥)).
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Solution
To solve the problem, we need to use the identities of trigonometric functions and their inverses.
Step 1: Rewrite the expression using the identities of cot and tan.
cot(tan^(-1)(2x) + cot^(-1)(2x)) = cot(arctan(2x) + arccot(2x))
Step 2: Use the property that arctan(x) + arccot(x) = π/2.
cot(π/2) = 0
So, cot(tan^(-1)(2x) + cot^(-1)(2x)) = 0 for all real x.
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