Point M is the point of intersection of all the 3 medians of a triangle ∆ ABC. The median drawn from vertex A intersects the side BC at point D and the lengths of AD and BC are 21 cm and 24 cm respectively. What is the sum of the lengths of BD and MD ?

If the coordinates of the vertices of the triangle ABC be A(-1,6), B(-3,-9), and C(5,-8) respectively. i) Find the coordinated of the midpoint of AB II) Find the equation of the median through C in the form ax+by+c=0

The distance of the point of concurrency of the median of a triangle from the vertex is 2cm, then the length of that median is

In the figure, ABC is a right  and right angle at B. AD & CE arethe two medians drawn from A and C respectively. If AC = 5 cmand AD  3 5 cm.2 Then the length of CE will be(A) 4 5 cm (B) 2 5 cm(C) 3 5 cm2 (D) 6 5 cm

AD is a median of triangle ABC and area of ∆ ADC =15𝑐𝑚2, then ar(∆ ABC) isa) 15 𝑐𝑚2 b) 22.5𝑐𝑚2 c) 30 𝑐𝑚2 d) 37.5 𝑐𝑚2

ABC triangle right angled at C. A line through the midpoint M of hypotenuse AB andparallel to BC intersects AC at D. (4)Show that:i) MD II BCii) CM = MA = ½ABiii) D is the midpoint of AC.