nation:In the given second example D = 36 and P = 3Duration of each day part = 122~14~X3~15~X5~17~29 – instance of equivalent prime hours7~19~31 – instance of equivalent prime hours11~23~XHence the answers is 2.
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nation:In the given second example D = 36 and P = 3Duration of each day part = 122~14~X3~15~X5~17~29 – instance of equivalent prime hours7~19~31 – instance of equivalent prime hours11~23~XHence the answers is 2.
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Here on earth, our 24-hour day is composed of two parts, each of 12 hours. Each hour in each part has a corresponding hour in the other part separated by 12 hours: the hour essentially measures the duration since the start of the daypart. For example, 1 hour in the first part of the day is equivalent to 13, which is 1 hour into the second part of the day.Now, consider the equivalent hours that are both prime numbers. We have 3 such instances for a 24-hour 2-part day:5~177~1911~23Accept two natural numbers D, P >1 corresponding respectively to a number of hours per day and the number of parts in a day separated by a space. D should be divisible by P, meaning that the number of hours per part (D/P) should be a natural number. Calculate the number of instances of equivalent prime hours. Output zero if there is no such instance. Note that we require each equivalent hour in each part in a day to be a prime number.Constraints:InputThe single line consists of two space-separated integers, D and P corresponding to the number of. hours per day and number of parts in a day respectivelyOutputOutput must be a single number, corresponding to the number of instances of equivalent prime number, as described aboveConstraints10 <= D < 5002 <= P < 50Example:Example 1:Input: 24 2Output: 3 Example 2:Input36 3Output2Explanation:In the given second example D = 36 and P = 3Duration of each day part = 122~14~X3~15~X5~17~29 – instance of equivalent prime hours7~19~31 – instance of equivalent prime hours11~23~XHence the answers is 2.
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