Solve the equation x, squared, minus, 10, x, minus, 11, equals, minus, 28x 2 −10x−11=−28 to the nearest tenth.

The given equation seems to be a bit unclear, but I'm assuming you're referring to the quadratic equation x^2 - 10x - 11 = -28.

Let's solve this step by step:

Step 1: Simplify the equation x^2 - 10x - 11 + 28 = 0 This simplifies to: x^2 - 10x + 17 = 0

Step 2: Identify the coefficients for the quadratic formula In the equation ax^2 + bx + c = 0, our a, b, and c are as follows: a = 1 (coefficient of x^2) b = -10 (coefficient of x) c = 17 (constant term)

Step 3: Plug these values into the quadratic formula The quadratic formula is x = [-b ± sqrt(b^2 - 4ac)] / (2a) So, x = [10 ± sqrt((-10)^2 - 4117)] / (2*1) This simplifies to: x = [10 ± sqrt(100 - 68)] / 2 x = [10 ± sqrt(32)] / 2 x = [10 ± 5.66] / 2

Step 4: Solve for x We have two possible solutions here: x = (10 + 5.66) / 2 = 7.83 (to the nearest tenth) x = (10 - 5.66) / 2 = 2.17 (to the nearest tenth)

So, the solutions to the equation x^2 - 10x + 17 = 0 are x = 7.8 and x = 2.2 (to the nearest tenth).