Knowee
Questions
Features
Study Tools

How many moles in 22.81 mL of liquid mercury (Hg)? Answer to 3 decimal places.𝜌(Hg) = 13.534 g.mL-1MW(Hg) = 200.59 g.mol-1

Question

How many moles in 22.81 mL of liquid mercury (Hg)? Answer to 3 decimal places.𝜌(Hg) = 13.534 g.mL-1MW(Hg) = 200.59 g.mol-1

🧐 Not the exact question you are looking for?Go ask a question

Solution

Para determinar cuántos moles hay en 22.81 mL de mercurio líquido (Hg), debemos seguir estos pasos:

  1. Calcular la masa del mercurio: Utilizamos la densidad (𝜌) para encontrar la masa (m). m=𝜌×volumen \text{m} = \text{𝜌} \times \text{volumen} Dado que 𝜌(Hg) = 13.534 g/mL y el volumen es 22.81 mL: m=13.534g/mL×22.81mL=308.51554g \text{m} = 13.534 \, \text{g/mL} \times 22.81 \, \text{mL} = 308.51554 \, \text{g}

  2. Calcular los moles de mercurio: Utilizamos la masa molar (MW) para convertir la masa en moles. moles=masamasa molar \text{moles} = \frac{\text{masa}}{\text{masa molar}} Dado que MW(Hg) = 200.59 g/mol: moles=308.51554g200.59g/mol=1.538moles \text{moles} = \frac{308.51554 \, \text{g}}{200.59 \, \text{g/mol}} = 1.538 \, \text{moles}

Por lo tanto, hay 1.538 moles en 22.81 mL de mercurio líquido.

This problem has been solved

Similar Questions

How many moles in 31.32 mL of liquid mercury (Hg)? Answer to 3 decimal places.

How many moles are there in 22.195 g of C6H12O6?Give your answer in moles and to three decimal places.(Molar mass of  C6H12O6 = 180.16 g mol-1)

How many moles of H+ are there in 1.980 g of H2SO4?Give your answer in moles and to three decimal places.(Molar mass of H2SO4 = 98.08 g mol−1)

If 14.5 grams of mercury was found in 200 L of lake Ontario water, then what is the concentration of mercury in parts per million? Question 3 options: 14.5 0.00145 72.5 7.25 725 0.0000725

A 500-mL sample of effluent from a chemical plant contains 26.1 μg of mercury. If the density of the effluent liquid is 1.073 g/mL, calculate the concentration of mercury in (a) molarity and (b) parts per million.

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.