Please explain to me on how to do this 600 𝑚𝑜𝑙 𝐶6𝐻12𝑂6 × 6 𝑚𝑜𝑙 𝐶𝑂2/1 𝑚𝑜𝑙 𝐶6𝐻12𝑂6 × 44.01 𝑔 𝐶𝑂2/1 𝑚𝑜𝑙 𝐶𝑂2 = 𝟏𝟓𝟖. 𝟒𝟒 𝒈 𝑪𝑶 Explain

This calculation is based on stoichiometry, which is a section of chemistry that involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.

In this case, we are given a reaction where 1 mole of glucose (C6H12O6) produces 6 moles of carbon dioxide (CO2). We are also given that the molar mass of CO2 is 44.01 g/mol.

Here are the steps to solve this:

1. Start with the given amount of glucose, which is 600 moles.

2. Use the stoichiometric ratio from the balanced chemical equation to convert from moles of glucose to moles of CO2. The ratio is 6 moles of CO2 for every 1 mole of glucose. So, multiply 600 moles of glucose by 6/1 to get 3600 moles of CO2.

3. Now, convert moles of CO2 to grams of CO2 using the molar mass. The molar mass of CO2 is 44.01 g/mol. So, multiply 3600 moles of CO2 by 44.01 g/mol to get 158,436 grams of CO2.

4. Finally, convert grams to kilograms since the answer is usually expressed in larger units for such large quantities. There are 1000 grams in a kilogram, so 158,436 grams is equal to 158.436 kilograms.

So, 600 moles of glucose will produce approximately 158.436 kilograms of CO2.