A particle having a charge of 1.6×10−19 1.6×10 −19   coulomb is moving with a speed of 7×107𝑚/𝑠 7×10 7 m/s   in a magnetic field of 4T perpendicular to it. Calculate the force experienced by the moving charged particle.2.24×10−12𝑁2.24×10 −12 N4.48×10−12𝑁4.48×10 −12 N4.48×10−11𝑁4.48×10 −11 N2.24×10−11𝑁2.24×10 −11 N

A charged particle of charge 4μC is moving perpendicular to a magnetic field with velocity 3 m/s. if it experiences a magnetic force of 3×10−3𝑁 3×10 −3 N , determine the magnitude of the magnetic field.

A particle with positive charge q = 2.08 10-18 C moves with a velocity v = (4î + 4ĵ − ) m/s through a region where both a uniform magnetic field and a uniform electric field exist.(a)Calculate the total force on the moving particle, taking B = (4î + 3ĵ + ) T and E = (3î − ĵ − 2) V/m. (Give your answers in N for each component.)Fx = NFy = NFz = N(b)What angle does the force vector make with the positive x-axis? (Give your answer in degrees counterclockwise from the +x-axis.) ° counterclockwise from the +x-axis(c)What If? For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.)Ex = V/mEy = V/mEz = V/m

An electron experiences a magnetic force of magnitude 4.60 x 10-15 N when moving at an angleof 600 with respect to a magnetic field of magnitude 3.50 x 10-3 T. Find the speed of theelectron.

Calculate the force on an electron that enters a uniform magnetic field of flux density 150 mT at a speed of 8.0 x 10^6 m/s in a perpendicular direction to the field.*1 point1.0 x 10^-13 N1.9 x 10^-13 N1.0 x 10^-12 N1.9 x 10^-12 N

A proton is moving through a magnetic field of magnitude 4.40 × 10–3 T. The protonexperiences only a magnetic force of 3.3 × 10–15 N. At a certain instant, it has a speed of4.25 × 105 m s–1. Determine the angle (less than 90°) between the proton's velocity and themagnetic field.