The output of the code will be ____. int i=5; printf(“%d %d %d”, i, i++, ++i); in c
Question
The output of the code will be ____. int i=5; printf(“%d %d %d”, i, i++, ++i); in c
Solution
The output of this code is undefined and depends on the compiler. This is because the order of evaluation of arguments in a function call is not specified in the C standard.
In the expression printf(“%d %d %d”, i, i++, ++i);, both i++ and ++i are modifying the same variable i without an intervening sequence point. This invokes undefined behavior according to the C standard.
So, different compilers may give different outputs for this code. It's generally recommended to avoid writing code that depends on the order of evaluation of function arguments, as this can lead to bugs that are difficult to find and fix.
Similar Questions
The output of the code will be ____. int i=5; printf(“%d %d %d”, i, i++, ++i); ans. 5 5 7 7 6 6 7 6 5 7 6 7
What will be the output of the following C code?#include <stdio.h>int main() { int i; for (i = 0; i < 5; i++); printf("%d\n", i); return 0;}
What is the output of the code given below?#include <stdio.h> void main() { int i; for (i = 5; i < 10; i++); printf("%d ", i);}Options5105 6 7 8 99
find the output of given code.#include <stdio.h>int main(){int a,b=110,c=20;printf("%d",a=b-=c*=5);return 0;}
What will be the output of the following code?int i;for (i = 0; i < 5; i++) { if (i == 3) { break; } printf("%d ", i);}
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.