The product of tow natural numbers is 17. what is the sum of the squares of their reciprocals?Options1 7/2891 113/2899 1/2891 1/2892 11/17

The two natural numbers whose product is 17 are 1 and 17. The reciprocal of a number is 1 divided by that number. So, the reciprocals of 1 and 17 are 1/1 = 1 and 1/17.

The square of a number is that number multiplied by itself. So, the squares of these reciprocals are 11 = 1 and (1/17)(1/17) = 1/289.

The sum of these squares is 1 + 1/289 = 290/289 = 1 1/289.

So, the correct option is 1 1/289.

The two natural numbers whose product is 17 are 1 and 17. The reciprocal of a number is 1 divided by that number. So, the reciprocals of 1 and 17 are 1/1 = 1 and 1/17 respectively.

The square of a number is that number multiplied by itself. So, the squares of these reciprocals are 11 = 1 and (1/17)(1/17) = 1/289.

The sum of these squares is 1 + 1/289 = 290/289 = 1 1/289.

So, the correct option is 1 1/289.