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Complete and balance the following half-reaction in acidic solution. Be sure to include the proper phases for all species within the reaction.Sn²⁺(aq)→Sn⁴⁺(aq)☐⁴⁻☐³⁻☐²⁻☐⁻☐⁺☐²⁺☐³⁺☐⁴⁺1234567890☐₁☐₂☐₃☐₄☐₅☐₆☐₇☐₈☐₉☐₀+()→⇌(s)(l)(g)(aq)OH⁻H⁺e⁻OH₃O⁺SnHH₂OReset

Question

Complete and balance the following half-reaction in acidic solution. Be sure to include the proper phases for all species within the reaction.Sn²⁺(aq)→Sn⁴⁺(aq)☐⁴⁻☐³⁻☐²⁻☐⁻☐⁺☐²⁺☐³⁺☐⁴⁺1234567890☐₁☐₂☐₃☐₄☐₅☐₆☐₇☐₈☐₉☐₀+()→⇌(s)(l)(g)(aq)OH⁻H⁺e⁻OH₃O⁺SnHH₂OReset

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Solution

The half-reaction is:

Sn²⁺(aq) → Sn⁴⁺(aq)

To balance this reaction in acidic solution, we need to add electrons to the right side because the oxidation state of Sn is increasing from +2 to +4. This means that Sn is losing electrons, which is an oxidation process.

So, the balanced half-reaction is:

Sn²⁺(aq) → Sn⁴⁺(aq) + 2e⁻

This reaction is balanced in terms of both mass and charge.

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