The maximum torque (τ) on a current-carrying coil in a magnetic field is given by the formula:

τ = n * B * A * I * sinθ

where:
n = number of turns in the coil = 100
B = magnetic field strength = 10 T
A = area of the coil = 500 x 10^-4 m^2
I = current in the coil = 2 A
θ = angle between the normal to the coil and the magnetic field. For maximum torque, this angle is 90 degrees, so sinθ = 1.

Substituting these values into the formula gives:

τ = 100 * 10 * (500 x 10^-4) * 2 * 1
τ = 1000 Nm

So, the maximum torque on the coil is 1000 Nm.

Question

The maximum torque (τ) on a current-carrying coil in a magnetic field is given by the formula:

τ = n * B * A * I * sinθ

where:
n = number of turns in the coil = 100
B = magnetic field strength = 10 T
A = area of the coil = 500 x 10^-4 m^2
I = current in the coil = 2 A
θ = angle between the normal to the coil and the magnetic field. For maximum torque, this angle is 90 degrees, so sinθ = 1.

Substituting these values into the formula gives:

τ = 100 * 10 * (500 x 10^-4) * 2 * 1
τ = 1000 Nm

So, the maximum torque on the coil is 1000 Nm.

Knowee AI · Accepted Answer

The maximum torque (τ) on a current-carrying coil in a magnetic field is given by the formula:

τ = n * B * A * I * sinθ

where:
n = number of turns in the coil = 100
B = magnetic field strength = 10 T
A = area of the coil = 500 x 10^-4 m^2
I = current in the coil = 2 A
θ = angle between the normal to the coil and the magnetic field. For maximum torque, this angle is 90 degrees, so sinθ = 1.

Substituting these values into the formula gives:

τ = 100 * 10 * (500 x 10^-4) * 2 * 1
τ = 1000 Nm

So, the maximum torque on the coil is 1000 Nm.

A rectangular coil of 100 turns and area 500 x 10-4 m2 carrying 2 A current isplaced in a uniform magnetic field of 10T. Find the maximum torque applyingon the coil.

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