Max Ones in a RowMax Score: 20Given a M x N binary matrix, find the 0-indexed position of the row that contains the maximum count of ones, and the number of ones in that row. In case there are multiple rows that have the maximum count of ones, the row with the smallest row number should be selected.Input FormatThe first line of input contains integers M and N separated by space. For the next M lines, each line contains N elements separated by spaces.Output FormatPrint the index of the row, followed by the number of ones in it.Constraints1 ≤ M, N ≤ 100ExampleInput

You will be given a 2-d Matrix, and you need to concatenate values of the row, let's say it as Array 'A', which will contain concatenated values of each row as each value.Now, you need to concatenate the values present in 'A'(in any order) so that the final concatenated number is the maximum of all numbers possible.Input FormatThe first input line contains an integer 'n' denoting the number of rows in the matrix.The second input line contains an integer 'm' denoting the number of columns in the matrix.Next, 'n' input lines contain 'm' space-separated integers denoting matrix elements.Output FormatOutput the final concatenated string.Constraints2 <= n <= 5002 <= m <= 5001<=matrix elements<=105Sample Input331 2 34 5 67 8 9Sample Output789456123ExplanationAfter concatenating the values of each row, we get : "123" , '456" , "789"Now there are many possibilities for concatenating the above 3 values as follows: "123456789" , "456123789" , "789456123" , etc.Out of all possibilities, only "789456123" is the maximum of all, hence this is our answer.

You are given an m x n matrix grid consisting of positive integers. You can move from a cell in the matrix to any other cell that is either to the bottom or to the right (not necessarily adjacent). The score of a move from a cell with the value c1 to a cell with the value c2 is c2 - c1.You can start at any cell, and you have to make at least one move.Return the maximum total score you can achieve. Example 1:Input: grid = [[9,5,7,3],[8,9,6,1],[6,7,14,3],[2,5,3,1]]Output: 9Explanation: We start at the cell (0, 1), and we perform the following moves:- Move from the cell (0, 1) to (2, 1) with a score of 7 - 5 = 2.- Move from the cell (2, 1) to (2, 2) with a score of 14 - 7 = 7.The total score is 2 + 7 = 9.Example 2:Input: grid = [[4,3,2],[3,2,1]]Output: -1Explanation: We start at the cell (0, 0), and we perform one move: (0, 0) to (0, 1). The score is 3 - 4 = -1. Constraints:m == grid.lengthn == grid[i].length2 <= m, n <= 10004 <= m * n <= 1051 <= grid[i][j] <= 105

Print the sum of row 1 of A and row N of B, row 2 of A and row (N-1) of B and so on.Constraints1 <= N, M <= 100-102 <= mat[i][j] <= 102

Find the maximum element in a given matrixinput formatm-no.of rown-no. of columnmatrix=[   ]output format: maximum element(integer)

Maximum sumSend FeedbackGiven an N*N matrix. The task is to find the index of the column with the maximum sum. That is the column whose sum of elements is maximum.Input FormatNN*N matrix in comma separated form for each row.Input : 5 1, 2, 3, 4, 5 5, 3, 1, 4, 2 5, 6, 7, 8, 9 0, 6, 3, 4, 12 9, 7, 12, 4, 3Output: Column 5 has the max sum of 31.Input : 3 1, 2, 3 4, 2, 1 5, 6, 7Output: Column 3 has the max sum of 11.