From her home, Liz would have to walk due north to get to her friend Roy's house and due east to get to her friend Hazel's house. It is 3 miles from Liz's house to Hazel's house and a straight-line distance of 4 miles from Roy's house to Hazel's house. How far is Liz's house from Roy's house? If necessary, round to the nearest tenth.
Question
From her home, Liz would have to walk due north to get to her friend Roy's house and due east to get to her friend Hazel's house. It is 3 miles from Liz's house to Hazel's house and a straight-line distance of 4 miles from Roy's house to Hazel's house. How far is Liz's house from Roy's house? If necessary, round to the nearest tenth.
Solution
This problem can be solved using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In this case, we can think of Liz's house, Roy's house, and Hazel's house as forming a right triangle. The distance from Liz's house to Hazel's house is one side of the triangle (3 miles), the distance from Liz's house to Roy's house is the other side, and the distance from Roy's house to Hazel's house is the hypotenuse (4 miles).
Let's denote the distance from Liz's house to Roy's house as x. According to the Pythagorean theorem, we have:
x^2 + 3^2 = 4^2
Solving this equation for x gives:
x^2 = 4^2 - 3^2 x^2 = 16 - 9 x^2 = 7
Taking the square root of both sides gives:
x = sqrt(7) ≈ 2.6
So, Liz's house is approximately 2.6 miles from Roy's house.
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