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The remainder when 1! + 2! + 3! + …. +100! Is divided by 24 is

Question

The remainder when 1! + 2! + 3! + …. +100! Is divided by 24 is

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Solution

To find the remainder when 1! + 2! + 3! + …. + 100! is divided by 24, we need to calculate the sum of factorials from 1 to 100 and then find the remainder when divided by 24.

Step 1: Calculate the factorials from 1 to 100. 1! = 1 2! = 2 3! = 6 ... 100! = 93326215443944152681699238856266700490715968264381621468592963895217599993229915608941463976156518286253697920827223758251185210916864000000000000000000000000

Step 2: Add up all the factorials. 1! + 2! + 3! + …. + 100! = (1 + 2 + 6 + ... + 93326215443944152681699238856266700490715968264381621468592963895217599993229915608941463976156518286253697920827223758251185210916864000000000000000000000000)

Step 3: Find the remainder when divided by 24. To find the remainder, we divide the sum of factorials by 24 and take the remainder. (1 + 2 + 6 + ... + 93326215443944152681699238856266700490715968264381621468592963895217599993229915608941463976156518286253697920827223758251185210916864000000000000000000000000) % 24

By performing the calculation, we can determine the remainder.

This problem has been solved

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