Analyze the following code: public class Test { public static void main(String[] args) { int[] oldList = {1, 2, 3, 4, 5}; reverse(oldList); for (int i = 0; i < oldList.length; i++) System.out.print(oldList[i] + " "); } public static void reverse(int[] list) { int[] newList = new int[list.length]; for (int i = 0; i < list.length; i++) newList[i] = list[list.length - 1 - i]; list = newList; } } Group of answer choicesThe program displays 1 2 3 4 5.The program displays 1 2 3 4 5 and then raises an ArrayIndexOutOfBoundsException.The program displays 5 4 3 2 1.The program displays 5 4 3 2 1 and then raises an ArrayIndexOutOfBoundsException.
Question
Analyze the following code: public class Test { public static void main(String[] args) { int[] oldList = {1, 2, 3, 4, 5}; reverse(oldList); for (int i = 0; i < oldList.length; i++) System.out.print(oldList[i] + " "); } public static void reverse(int[] list) { int[] newList = new int[list.length]; for (int i = 0; i < list.length; i++) newList[i] = list[list.length - 1 - i]; list = newList; } } Group of answer choicesThe program displays 1 2 3 4 5.The program displays 1 2 3 4 5 and then raises an ArrayIndexOutOfBoundsException.The program displays 5 4 3 2 1.The program displays 5 4 3 2 1 and then raises an ArrayIndexOutOfBoundsException.
Solution
The program displays 1 2 3 4 5.
This is because the reverse method does not actually change the original array 'oldList'. In Java, when you pass an array to a method, you are passing the reference to the array, not the actual array itself. So when the line 'list = newList;' is executed, it does not change the original array, but only changes the reference 'list' to point to 'newList'. After the reverse method is finished, 'oldList' still points to the original array. Therefore, the original array is printed, not the reversed array.
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