The vertex of this parabola is at (-4, -1). When the y-value is 0, the x-value is 2. What is the coefficient of the squared term in the parabola's equation?A.-3B.6C.3D.-6SUBMITarrow_backPREVIOUS
Question
The vertex of this parabola is at (-4, -1). When the y-value is 0, the x-value is 2. What is the coefficient of the squared term in the parabola's equation?A.-3B.6C.3D.-6SUBMITarrow_backPREVIOUS
Solution
The equation of a parabola in vertex form is y = a(x - h)² + k, where (h, k) is the vertex of the parabola.
Given that the vertex of the parabola is (-4, -1), we can substitute h = -4 and k = -1 into the equation to get y = a(x + 4)² - 1.
We also know that when y = 0, x = 2. Substituting these values into the equation gives us 0 = a(2 + 4)² - 1.
Solving this equation for a will give us the coefficient of the squared term in the parabola's equation.
0 = a(6)² - 1 1 = 36a a = 1/36
Therefore, none of the options A, B, C, D are correct. The coefficient of the squared term in the parabola's equation is 1/36.
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