To solve this problem, we need to look at each gene separately.

1. For the A gene:
The first parent has Aa and the second parent has AA. The only possible combination for the offspring to get from the first parent is A (since the second parent can only give A). So the probability is 1.

2. For the B gene:
The first parent has Bb and the second parent has bb. The offspring needs to get b from both parents to be bb. The probability of getting b from the first parent is 1/2 (since it can give either B or b) and the probability of getting b from the second parent is 1 (since it can only give b). So the total probability is 1/2 * 1 = 1/2.

3. For the D gene:
The first parent has Dd and the second parent has Dd. The offspring needs to get d from both parents to be dd. The probability of getting d from the first parent is 1/2 (since it can give either D or d) and the probability of getting d from the second parent is 1/2 (since it can give either D or d). So the total probability is 1/2 * 1/2 = 1/4.

To get the total probability of the offspring being AAbbdd, we multiply the probabilities of each gene: 1 * 1/2 * 1/4 = 1/8. So the answer is 1/8.

Question

To solve this problem, we need to look at each gene separately.

1. For the A gene: 
The first parent has Aa and the second parent has AA. The only possible combination for the offspring to get from the first parent is A (since the second parent can only give A). So the probability is 1.

2. For the B gene: 
The first parent has Bb and the second parent has bb. The offspring needs to get b from both parents to be bb. The probability of getting b from the first parent is 1/2 (since it can give either B or b) and the probability of getting b from the second parent is 1 (since it can only give b). So the total probability is 1/2 * 1 = 1/2.

3. For the D gene: 
The first parent has Dd and the second parent has Dd. The offspring needs to get d from both parents to be dd. The probability of getting d from the first parent is 1/2 (since it can give either D or d) and the probability of getting d from the second parent is 1/2 (since it can give either D or d). So the total probability is 1/2 * 1/2 = 1/4.

To get the total probability of the offspring being AAbbdd, we multiply the probabilities of each gene: 1 * 1/2 * 1/4 = 1/8. So the answer is 1/8.

Knowee AI · Accepted Answer

To solve this problem, we need to look at each gene separately.

1. For the A gene: 
The first parent has Aa and the second parent has AA. The only possible combination for the offspring to get from the first parent is A (since the second parent can only give A). So the probability is 1.

2. For the B gene: 
The first parent has Bb and the second parent has bb. The offspring needs to get b from both parents to be bb. The probability of getting b from the first parent is 1/2 (since it can give either B or b) and the probability of getting b from the second parent is 1 (since it can only give b). So the total probability is 1/2 * 1 = 1/2.

3. For the D gene: 
The first parent has Dd and the second parent has Dd. The offspring needs to get d from both parents to be dd. The probability of getting d from the first parent is 1/2 (since it can give either D or d) and the probability of getting d from the second parent is 1/2 (since it can give either D or d). So the total probability is 1/2 * 1/2 = 1/4.

To get the total probability of the offspring being AAbbdd, we multiply the probabilities of each gene: 1 * 1/2 * 1/4 = 1/8. So the answer is 1/8.

What is the probability that a cross between AaBbDd and AAbbDd parents would produce an AAbbdd offspring?Group of answer choices1/81/401/16

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