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Let x = 3 tan(๐œƒ), โˆ’๐œ‹/2 < ๐œƒ < ๐œ‹/2. Then dx =

Question

Let x = 3 tan(๐œƒ), โˆ’๐œ‹/2 < ๐œƒ < ๐œ‹/2. Then dx =

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Solution

To find dx, we need to take the derivative of x with respect to ๐œƒ.

The derivative of tan(๐œƒ) with respect to ๐œƒ is sec^2(๐œƒ).

So, the derivative of 3 tan(๐œƒ) with respect to ๐œƒ is 3 sec^2(๐œƒ).

Therefore, dx = 3 sec^2(๐œƒ) d๐œƒ.

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