Laplace transform of cos(4t) u(t) is1 points/(s^2+16)4/(s^2+16)s/(s^2-16)4/(s^2-16)
Question
Laplace transform of cos(4t) u(t) is1 points/(s^2+16)4/(s^2+16)s/(s^2-16)4/(s^2-16)
Solution
The Laplace transform of cos(4t)u(t) is s/(s^2+16).
Here's the step-by-step solution:
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The Laplace transform of cos(at)u(t) is given by the formula s/(s^2+a^2).
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In this case, a = 4.
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Substituting a = 4 into the formula, we get s/(s^2+4^2) = s/(s^2+16).
So, the Laplace transform of cos(4t)u(t) is s/(s^2+16).
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