Find the largest possible number M such that 3452%M is equal to 1287%M.
Question
Find the largest possible number M such that 3452%M is equal to 1287%M.
Solution
To solve this problem, we need to find the largest possible number M such that the remainders when 3452 and 1287 are divided by M are the same.
This is equivalent to finding the largest M such that 3452 - 1287 is divisible by M.
So, we subtract 1287 from 3452 to get 2165.
The largest possible M is therefore the largest factor of 2165, which is 2165 itself.
So, M = 2165.
Similar Questions
Given 2 numbers a and b, a%b represents the remainder when a is divided by b.For example, 12%5 = 2 because 12 when divided by 5 leaves a remainder of 2.Following are some rules of modulo arithmetic:(ab) % c = (ba) % c(a+b) % c = (b+a) % c(a*b) % c = (a%c * b%c)%c(ab * db) % c = (ad)b % c = (ad % c)b % cFind the largest possible number M such that 3452%M is equal to 1287%M.
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