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Given the head of a linked list, we repeatedly delete consecutive sequences of nodes that sum to 0 until there are no such sequences.After doing so, return the head of the final linked list.  You may return any such answer.

Question

Given the head of a linked list, we repeatedly delete consecutive sequences of nodes that sum to 0 until there are no such sequences.After doing so, return the head of the final linked list.  You may return any such answer.

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Solution

Sure, I can help with that. Here is a Python solution using a dictionary to keep track of the cumulative sum of the nodes.

class ListNode:
    def __init__(self, x):
        self.val = x
        self.next = None

def removeZeroSumSublists(head):
    dummy = ListNode(0)
    dummy.next = head
    cum = 0
    seen = {0: dummy}
    node = dummy
    while node:
        cum += node.val
        seen[cum] = node
        node = node.next
    node = dummy
    cum = 0
    while node:
        cum += node.val
        if cum in seen:
            node.next = seen[cum].next
        node = node.next
    return dummy.next

Here's how it works:

  1. We initialize a dummy node with value 0 and set it as the previous node of the head. This is to handle the case where the entire linked list needs to be deleted.

  2. We initialize a dictionary seen to keep track of the cumulative sum of the nodes. The key is the cumulative sum and the value is the node.

  3. We

This problem has been solved

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