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What is the distance between a 900pC and 200nC point charges if the electric force generated is at 3x10-4 N?Group of answer choices0.0054 cm0.07 cm0.07 m0.0054 m

Question

What is the distance between a 900pC and 200nC point charges if the electric force generated is at 3x10-4 N?Group of answer choices0.0054 cm0.07 cm0.07 m0.0054 m

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Solution

The force between two charges is given by Coulomb's law:

F = k * |q1*q2| / r²

where:

  • F is the magnitude of the force between the charges,
  • k is Coulomb's constant (approximately 8.99*10^9 N m²/C²),
  • q1 and q2 are the charges,
  • r is the distance between the charges.

We can rearrange the formula to solve for r:

r = sqrt(k * |q1*q2| / F)

Given:

  • F = 3*10^-4 N,
  • q1 = 900 pC = 900*10^-12 C,
  • q2 = 200 nC = 200*10^-9 C,
  • k = 8.99*10^9 N m²/C².

Substituting these values in:

r = sqrt((8.9910^9 N m²/C² * 90010^-12 C * 20010^-9 C) / 310^-4 N) r = sqrt((1.619110^-1 m²) / 310^-4 N) r = sqrt(0.5397 m) r = 0.7346 m

So, the distance between the charges is approximately 0.07 m.

This problem has been solved

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