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Test: Probability- 4 - Question 10 SaveThere are two bags, one of them contains 5 red and 7 white balls and the other 3 red and 12 white balls, and a ball is to be drawn from one or the other of the two bags. Find the chance of drawing a red ball.

Question

Test: Probability- 4 - Question 10 SaveThere are two bags, one of them contains 5 red and 7 white balls and the other 3 red and 12 white balls, and a ball is to be drawn from one or the other of the two bags. Find the chance of drawing a red ball.

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Solution

To solve this problem, we need to use the law of total probability.

Step 1: Calculate the probability of drawing a ball from each bag. Since the problem doesn't specify, we'll assume it's equally likely to draw from either bag. So, the probability of drawing from Bag 1 (P(B1)) is 0.5 and the probability of drawing from Bag 2 (P(B2)) is also 0.5.

Step 2: Calculate the probability of drawing a red ball from each bag. In Bag 1, there are 5 red balls out of a total of 12 balls (5 red + 7 white), so the probability of drawing a red ball from Bag 1 (P(R|B1)) is 5/12. In Bag 2, there are 3 red balls out of a total of 15 balls (3 red + 12 white), so the probability of drawing a red ball from Bag 2 (P(R|B2)) is 3/15 or 1/5.

Step 3: Use the law of total probability to find the overall probability of drawing a red ball. The law of total probability states that P(A) = P(B1)*P(A|B1) + P(B2)*P(A|B2). Substituting in our values, we get P(R) = P(B1)P(R|B1) + P(B2)P(R|B2) = 0.5(5/12) + 0.5(1/5) = 0.2083 + 0.1 = 0.3083.

So, the chance of drawing a red ball is approximately 0.3083 or 30.83%.

This problem has been solved

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